RE: Why you absolutely share the same birthday with someone else on Steemit! The Birthday Paradox, explained
Im pretty sure you're off here. Unless im misunderstanding.
Youre saying that in a room with 100 people in it, the probability is 100% that at least two will have the same birthday.
But this is not true. IMagine that 30 were born in january (1 on each day), 28 on feb (again one on each day) 30 in march (agian one on each day) and 12 in april (again one on each day). Since there is a less than zero chance of 100 people in a room having precisely those birthdays, there must be less than 100% chance of at least 2 of them having the same Bd.
In fact, there are many ways I can arrange 100 people so that no two will have the same BD.
It seems to me that to get to 100%, you must have 366 people in the room, no? Thats the least amount of people that you can have where no possible arrangement would result in all of them having different birthdays.. With just 365 people, the odds would be 365! to 1 of having 365 different (there fore no same ) BDs (which granted is minute but still not 0)
IN anycase, upvoted for the brain twister.
The percentages were rounded to two decimal places for ease of reading the table, as I indicated above the table. Rounding, of course, sacrifices accuracy. Probability for 100 people is 99.99997%, which rounds to 100.00% at two decimal places. To reach true 100%, no rounding, you need 366 as you indicated.
To make this abundantly clear, I will add an addendum. Thanks!
im guessing this was probably apparent from the tails on the graph, which is fairly small on my phone.... carry on...
its kind of nuts that you get so much of the probablilty in the first 100